A) \[9\mu F\]
B) \[1\mu F\]
C) \[4.5\mu F\]
D) \[6\mu F\]
Correct Answer: A
Solution :
The given circuit is equivalent to three capacitors connected in parallel, hence \[C={{C}_{1}}+{{C}_{2}}+{{C}_{3}}\] C = 3 + 3 + 3 = 9 \[\mu F\]You need to login to perform this action.
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