A) R only
B) C only
C) L only
D) R, C and L
Correct Answer: A
Solution :
Let E be the emf of the series LCR circuit, then current \[(I)\] is given by \[I=\frac{E}{Z}\] where Z is impedance. \[Z=\sqrt{{{R}^{2}}+{{\left( \omega L-\frac{1}{\omega C} \right)}^{2}}}\] At resonance \[\omega L=\frac{1}{\omega C}\] \[\therefore \] Z = R Hence, current \[I=\frac{E}{R}\], depends on the value of R only.You need to login to perform this action.
You will be redirected in
3 sec