A) \[2\,mu\]
B) \[\sqrt{3}\,mu\]
C) \[\,mu\]
D) \[\frac{\,mu}{\sqrt{3}}\]
Correct Answer: B
Solution :
Let body be projected with an initial velocity u, at an angle \[{{60}^{o}}\] with the horizontal, then change in momentum \[(\Delta p)\] is given by \[\Delta p=mu\,\sin {{60}^{o}}-(-mu\,\sin {{60}^{o}})\] \[\Delta p=2\,mu\,\sin {{60}^{o}}\] \[\Rightarrow \] \[\Delta p=2\,\,mu\,\frac{\sqrt{3}}{2}\] \[\Rightarrow \] \[\Delta p=\,\sqrt{3}\,mu\]You need to login to perform this action.
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