A) \[Mgl\]
B) \[\frac{Mgl}{2}\]
C) \[\frac{Mgl}{4}\]
D) \[2Mgl\]
Correct Answer: B
Solution :
When a wire is stretched, work is done against the interatomic forces, this work is stored in the wire in the form of mechanical energy. Mechanical energy = (average force) x (increase in length). \[E=\frac{1}{2}Fl\] where E = Mg \[\therefore \] \[E=\frac{1}{2}Mgl\]You need to login to perform this action.
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