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AMU Medical AMU Solved Paper-2002

  • question_answer
    A proton, electron and an a-particle is accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to the magnetic field B. The ratio of their kinetic energies is

    A)  2 1 1    

    B)                                  2 2 1

    C)  1 2 1                                     

    D)  1 1 2

    Correct Answer: D

    Solution :

                     Kinetic energy of a charged particle is, KE = qV Since, potential is same in all three cases, hence ratio is \[K{{E}_{1}}:K{{E}_{2}}:K{{E}_{3}}={{q}_{p}}:{{q}_{e}}:{{q}_{\alpha }}\]                 = e : e : 2e                 = 1 : 1 : 2


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