A) Ni
B) Co
C) Fe
D) Zn
Correct Answer: C
Solution :
Key Idea The magnetic moment is given as\[\mu =\sqrt{n\,(n+2)}\]where n is number of unpaired electrons. So, magnetic moment depends upon the number of unpaired electrons.Ni(28) | [Ar] \[3{{d}^{8}}4{{s}^{2}}\] | 2 unpaired electrons |
Co(27) | [Ar] \[3{{d}^{7}}4{{s}^{2}}\] | 3 unpaired electrons |
Fe(26) | [Ar] \[3{{d}^{6}}4{{s}^{2}}\] | 4 unpaired electrons |
Zn(30) | [Ar] \[3{{d}^{10}}4{{s}^{2}}\] | No unpaired electrons. |
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