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AMU Medical AMU Solved Paper-2002

  • question_answer
    The alternating voltage and current in an electric circuit are respectively given by \[E=100\,\,\sin \,100\,\pi t\] \[\text{I }=\text{ 5 sin 100}\pi \text{t}\] The reactance of the circuit will be

    A)  200                                       

    B)  0.050

    C)  10                                         

    D)   zero

    Correct Answer: A

    Solution :

                     The impedance of circuit is                 \[Z=\frac{{{E}_{V}}}{{{I}_{V}}}\]                 \[{{E}_{V}}=\frac{{{E}_{m}}}{\sqrt{2}}=\frac{100}{\sqrt{2}}\]                 \[{{I}_{V}}=\frac{{{I}_{m}}}{\sqrt{2}}=\frac{5}{\sqrt{2}}\] \[\therefore \]  \[Z=\frac{100/\sqrt{2}}{5/\sqrt{2}}=20\,\,\Omega \]


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