AMU Medical AMU Solved Paper-2002

  • question_answer
    To deposit one equivalent weight of silver at cathode the charge required will be

    A)  \[9.65\times {{10}^{4}}C\]          

    B)  \[9.65\times {{10}^{3}}C\]

    C)  \[9.65\times {{10}^{5}}C\]          

    D)  \[9.65\times {{10}^{7}}C\]

    Correct Answer: A

    Solution :

                     Key Idea One faraday is that quantity of electricity which can be deposited or liberated weight equal to equivalent weight.                 faraday = 96500 C Let the required charge to deposit one equivalent weight of silver be Q. Equivalent weight \[=\frac{Q}{F}\]                 \[1=\frac{Q}{96500}\]    \[(1\,\,F=96500\,\,C)\]                 \[Q=96500\,C=9.65\times {{10}^{4}}C\]


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