A) \[1.25\times {{10}^{-5}}\]
B) \[1.56\times {{10}^{-10}}\]
C) \[1.\times {{10}^{-10}}\]
D) \[1.44\times {{10}^{-10}}\]
Correct Answer: B
Solution :
Key Idea For a binary electrolyte \[{{K}_{sp}}={{s}^{2}}\] where s is solubility in mol/L \[{{K}_{sp}}\] is solubility product. \[AgCl\] is a binary electrolyte. Here, \[s=1.25\times {{10}^{-5}}mol/L\] \[\therefore \] \[{{K}_{sp}}={{(1.25\times {{10}^{-5}})}^{2}}\] \[=1.56\times {{10}^{-10}}\] Note - For a ternary electrolyte \[{{K}_{sp}}=4{{s}^{3}}\].
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