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AMU Medical AMU Solved Paper-2002

  • question_answer
    The maximum velocity of a simple harmonic motion represented by \[\left( 100\,t\,+\frac{\pi }{6} \right)m\]is given by

    A)  300                                       

    B)  \[\frac{3\pi }{6}\]

    C)  100                                       

    D)  \[\frac{\pi }{6}\]

    Correct Answer: A

    Solution :

                     Rate of change of displacement is equal to velocity. Given,   \[y=3\,\sin \left( 100\,t+\frac{\pi }{6} \right)\] \[\therefore \]  \[v=\frac{dy}{dt}=300\,\cos \left( 100\,t+\frac{\pi }{6} \right)\] Value of \[\cos \theta \] lies between -1 to + 1, hence maximum value of velocity is 300 m/s.


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