A) 2.7 kg
B) 1.8 kg
C) 3.58 kg
D) 4.5 kg
Correct Answer: C
Solution :
Combustion of butane takes place as \[{{C}_{4}}{{H}_{10}}\] \[+\frac{13}{2}{{O}_{2}}\xrightarrow{{}}4C{{O}_{2}}+5{{H}_{2}}O\] \[4\times 12+10\times 1\] \[=48+10\] \[=58\,g\] Now, 58 kg \[{{C}_{4}}{{H}_{10}}\] require \[{{O}_{2}}\] \[=\frac{13}{2}\times 32=208\,\,kg\] \[\therefore \,\,1\,kg{{C}_{4}}{{H}_{10}}\] require \[{{O}_{2}}\] \[=\frac{208}{58}=3.58\,\,kg\]
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