AMU Medical AMU Solved Paper-2002

  • question_answer
    \[CuS{{O}_{4}}\] dissolves in \[N{{H}_{3}}\]due to formation of

    A)  \[Cu{{(OH)}_{2}}\]

    B)  \[[Cu{{(N{{H}_{3}})}_{4}}{{(OH)}_{2}}]\]

    C)  \[[Cu{{(N{{H}_{3}})}_{4}}]S{{O}_{4}}\]

    D)  \[CuO\]

    Correct Answer: C

    Solution :

                     When copper sulphate is treated with excess of ammonia solution, it gives a deep blue solution due to the formation of tetramine copper (II) sulphate complex. \[CuS{{O}_{4}}+4N{{H}_{3}}\xrightarrow{{}}\,\underset{\begin{smallmatrix}  \begin{array}{*{35}{l}}    tetraamine\text{ }copper\text{ }\left( II \right)  \\    sulphate\text{ }deep  \\ \end{array} \\  blue\text{ }complex \end{smallmatrix}}{\mathop{[Cu{{(N{{H}_{3}})}_{4}}]S{{O}_{4}}}}\,\] Note - Tetramine copper (II) sulphate is used for making artificial, rayon, artificial silk, cupra silk.


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