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AMU Medical AMU Solved Paper-2002

  • question_answer
    A metallic wire of length L metre extends by \[l\]metre when stretched by suspending a weight of Mg to it. Then the mechanical energy stored in the wire is

    A)  \[Mgl\]                               

    B)  \[\frac{Mgl}{2}\]

    C)  \[\frac{Mgl}{4}\]                                            

    D)  \[2Mgl\]

    Correct Answer: B

    Solution :

                     When a wire is stretched, work is done against the interatomic forces, this work is stored in the wire in the form of mechanical energy. Mechanical energy = (average force)                                                 x (increase in length).                 \[E=\frac{1}{2}Fl\] where   E = Mg \[\therefore \]  \[E=\frac{1}{2}Mgl\]


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