A) \[45{}^\circ C\]
B) \[55{}^\circ C\]
C) \[60{}^\circ C\]
D) \[65{}^\circ C\]
Correct Answer: B
Solution :
Temperature gradient = ? Given, \[{{\theta }_{2}}={{100}^{o}}C\], \[{{\theta }_{1}}={{0}^{o}}C,\] \[l=20\,cm\] \[\therefore \] Temperature gradient \[=\frac{100}{20}={{5}^{o}}\,C/m\] Temperature difference at point C is \[={{100}^{o}}-{{45}^{o}}={{55}^{o}}C\].You need to login to perform this action.
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