A) 1.1
B) 0.8
C) 0.001
D) 0.01
Correct Answer: D
Solution :
Torque acting on loop is given by \[\tau =IAB\,\sin \theta \] where \[I\] is current, A the area and B the magnetic field intensity. Given, \[I=10\,A\], \[A=0.01\,\,{{m}^{2}}\], \[B=0.1\,T\], \[\theta ={{90}^{o}}\] \[\therefore \] \[\tau =10\times 0.01\times 0.1\times \sin \,{{90}^{o}}\] \[\Rightarrow \] \[\tau =0.01\,\,N-m\]You need to login to perform this action.
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