A) 9
B) 7
C) < 7
D) > 8
Correct Answer: C
Solution :
Key Idea \[pH=-\log \,[{{H}^{+}}]\] \[{{H}^{+}}={{10}^{-8}}mol/L\] So, in aqueous solution, in \[{{H}^{+}}\] ion concentration of acid, H+ ion concentration of water is also added. Hence, total \[[{{H}^{+}}]\] of acid \[=({{10}^{-8}}+{{10}^{-7}})\,\,mol/L\] \[={{10}^{-8}}(1+10)\] \[=11\times {{10}^{-8}}mol/L\] Therefore, \[pH=-\log \,[11\times {{10}^{-8}}]\] \[=-\log \,11+8\,\,\log \,\,10\] \[=-1.0414+8\] \[pH=6.9586\]
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