A) potential difference between the plates becomes 2V
B) energy stored in the system increases
C) charges on the free plates are enhanced
D) charges on the plates connected together are destroyed
Correct Answer: A
Solution :
We know that Potential \[V=\frac{energy\,\left( Q \right)}{charge\text{ }\left( q \right)}\] Dimensions of energy \[(Q)=[M{{L}^{2}}{{T}^{-2}}]\] Dimensions of charge (q) = [IT] \[\therefore \] Dimensions of potential \[V=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[IT]}\] Dimensions of potential \[V=[M{{L}^{2}}{{T}^{-3}}{{I}^{-1}}]\]You need to login to perform this action.
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