A) 0.5 m
B) 1.0m
C) 1.5m
D) 2.0m
Correct Answer: A
Solution :
For open pipe, fundamental frequency (n) is \[{{n}_{1}}=\frac{3v}{2l}=3{{n}_{1}}\] where I is length of pipe. For second overtone \[{{n}_{2}}=\frac{3v}{2l}=3{{n}_{1}}\] Given, v = 333 m/s, \[{{n}_{1}}=333\,Hz\] \[\frac{3\times 333}{2l}=3\times 333\] \[\Rightarrow \] \[l=\frac{2}{l}=0.5\,m\]You need to login to perform this action.
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