A) At STP
B) When volume is 22.4 L
C) At 6.1 K
D) When R has no unit
Correct Answer: C
Solution :
Key Idea According to ideal gas equation \[pV=nRT\] \[p=\frac{n}{V}RT\] Here, \[n=2\,\,mol\] \[V=1\,\,L\] p = 1 atm R = 0.0821 L atm \[mo{{l}^{-1}}{{K}^{-1}}\] Put these values in the above formula \[p=\frac{n}{V}RT\] \[1=2\times 0.0821\times T\] \[T=\frac{1}{0.1642}\] \[T=6.09\,K\] \[T\approx 6.1\,K\]You need to login to perform this action.
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