A) 1
B) 4
C) \[\frac{1}{4}\]
D) \[\frac{1}{2}\]
Correct Answer: B
Solution :
Key Idea According to ideal gas equation \[pV=nRT\] \[pV=\frac{W}{M}RT\] \[pM=\frac{W}{V}RT\] \[pM=dRT\left( Density=\frac{mass}{valume} \right)\] Here, the density of gas A is twice of that of gas B and mol. wt. of gas A is half of that of gas B. From the equation \[pM=dRT\] \[p\propto \frac{d}{M}\] \[\frac{{{p}_{A}}}{{{p}_{B}}}=\frac{{{d}_{A}}}{{{d}_{B}}}\times \frac{{{M}_{B}}}{{{M}_{A}}}=\frac{2d}{d}\times \frac{M}{M/2}\] \[\frac{{{p}_{A}}}{{{p}_{B}}}=4\]You need to login to perform this action.
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