A) I and II
B) III and IV
C) II, III and IV
D) III and IV and I
Correct Answer: C
Solution :
Key Idea Isoelectronic structures have same number of electrons. (i) \[CH_{3}^{+}\] Number of electrons are \[6+3\times 1-1=8\] (ii) \[{{H}_{3}}{{O}^{+}}\] Number of electrons are \[3\times 1+8-1=10\] (iii) \[N{{H}_{3}}\] Number of electrons are \[7+3\times 1=10\] (iv) \[CH_{3}^{-}\] Number of electrons are \[6+3\times 1+1=10\] In \[{{H}_{3}}{{O}^{+}},\,N{{H}_{3}}\] and \[CH_{3}^{-}\] number of electrons are same therefore, these are isoelectronic structure.You need to login to perform this action.
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