A) 8J
B) 28 J
C) 18 J
D) 10 J
Correct Answer: C
Solution :
Work done (IV) = Force (F) ? displacement Given, \[\vec{F}=6\,\hat{i}+5\hat{j}\], \[d=3\,\hat{i}-2\hat{k}\] Taking scalar product, we get \[\vec{W}=\vec{F}.\,\,\vec{d}\] \[\therefore \] \[W=(6\,\hat{i}+5\hat{j}).\,\,(3\hat{i}-2\hat{k})\] Using, \[\hat{i}\,.\,\,\hat{i}=1\], \[\hat{i}\,.\,\,\hat{k}=0\] \[\hat{j}\,.\,\,\hat{i}=0\], \[\hat{j}\,.\,\,\hat{j}=1\], \[\hat{k}\,.\,\,\hat{k}=1\]You need to login to perform this action.
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