A) 400
B) 300
C) 200
D) 100
Correct Answer: D
Solution :
On placing a uniform glass plate of refractive index \[(\mu )\], the additional path difference introduced is \[(\mu -1)t\], where t is thickness of glass plate. \[\therefore \] Number of fringes shifted \[N=\frac{(\mu -1)}{\lambda }\,t\] Given, \[\mu =1.5\], \[t=0.1\,mm=0.1\times {{10}^{-3}}m\], \[\lambda =500\,\,nm=500\times {{10}^{-9}}m\] \[\therefore \] \[N=\frac{(1.5-1)}{500\times {{10}^{-9}}}\times 0.1\times {{10}^{-3}}\] \[\Rightarrow \] N = 100 fringesYou need to login to perform this action.
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