A) 45
B) 91
C) 19
D) 54
Correct Answer: D
Solution :
The thermal resistance R is given by \[R=\frac{l}{K\,A}\]where I is length of conducting material, K the coefficient of thermal conductivity, A the area Given, \[{{R}_{1}}={{R}_{2}}\] \[\frac{{{K}_{1}}{{A}_{1}}}{{{d}_{1}}}=\frac{{{K}_{2}}{{A}_{2}}}{{{d}_{2}}}\] Given, \[{{A}_{1}}={{A}_{2}}\], \[{{K}_{1}}:{{K}_{2}}=5:4\] \[\therefore \] \[\frac{{{d}_{1}}}{{{d}_{2}}}=\frac{{{K}_{1}}{{A}_{1}}}{{{K}_{2}}{{A}_{2}}}=\frac{5}{4}\]
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