A) 0.10 m
B) 0.06 m
C) 0.20 m
D) 0.25 m
Correct Answer: A
Solution :
Force due to magnetic field provides the required centripetal force to the ions. \[\therefore \]Centripetal force = force due to magnetic field \[\frac{m{{v}^{2}}}{r}=evB\,\sin \theta \] Given, \[\theta ={{90}^{o}},\frac{e}{m}=5\times {{10}^{7}}\,C/kg\], \[B=4\times {{10}^{-2}}T\], \[v=2\times {{10}^{5}}m/s\] \[\therefore \] \[r=\frac{mv}{eB}\] \[\Rightarrow \] \[r=\frac{2\times {{10}^{5}}}{5\times {{10}^{7}}\times 4\times {{10}^{-2}}}=0.1\,m\]You need to login to perform this action.
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