A) \[\text{4}\times \text{l}{{\text{0}}^{-\text{5}}}\text{Wb}/{{\text{m}}^{\text{2}}}\]
B) \[\text{2}\times \text{l}{{\text{0}}^{-\text{5}}}\text{Wb}/{{\text{m}}^{\text{2}}}\]
C) \[3\times {{10}^{-5}}\,Wb/{{m}^{2}}\]
D) \[\text{8}\times \text{l}{{\text{0}}^{-5}}\text{Wb}/{{\text{m}}^{\text{2}}}\]
Correct Answer: A
Solution :
Intensity of magnetic field produced due to straight current carrying wire will be \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{2I}{r}\] Given, \[I=20\,A\], r = 10 cm \[=10\times {{10}^{-2}}m\] \[\therefore \] \[B={{10}^{-7}}\times \frac{2\times 20}{10\times {{10}^{-2}}}\] \[=4\times {{10}^{-5}}Wb/{{m}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec