A) 180 kJ
B) 186.4 kJ
C) 166.0 kJ
D) 160 kJ
Correct Answer: C
Solution :
Key Idea The relation between \[\Delta H\] and \[\Delta E\] is given by \[\Delta H=\Delta E+\Delta {{n}_{g}}\,RT\]where \[\Delta {{n}_{g}}\] change in the number of gaseous moles. For the reaction \[CaC{{O}_{3}}(s)CaCO(s)+C{{O}_{2}}(g)\] \[\Delta H=176\,\,kJ\,mol\] \[\Delta \,{{n}_{g}}=1-0=1\] \[=273+927=1200\,K\] \[R=8.3\times {{10}^{-3}}\,kJ\,mo{{l}^{-1}}{{K}^{-1}}\] Put these value in the above equation \[176=\Delta E+1\times 8.31\times {{10}^{-3}}\times 1200\] \[=\Delta E+9.972\] \[\Delta E=176-9.972=166.03\,\,kJ\]You need to login to perform this action.
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