A) \[\text{9}\times \text{1}{{0}^{\text{1}0}}\text{ J}\]
B) \[\text{9}\times \text{1}{{0}^{\text{11}}}\text{ J}\]
C) \[\text{9}\times \text{1}{{0}^{\text{12}}}\text{ J}\]
D) \[\text{9}\times \text{1}{{0}^{13}}\text{J}\]
Correct Answer: D
Solution :
From Einsteins mass-energy equivalence we have \[\Delta E=\Delta m{{c}^{2}}\]where \[\Delta m\] is change in mass, c the speed of light. Given, \[\Delta m=\frac{0.1}{100}={{10}^{-3}}kg\] \[\Delta \,E={{10}^{-3}}\times {{(3\times {{10}^{8}})}^{2}}\] \[=9\times {{10}^{3}}J\]
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