A) 100 cc
B) 400 cc
C) 104 cc
D) 2.5 cc
Correct Answer: D
Solution :
From ideal gas law, we get \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}{{V}_{2}}}{{{T}_{2}}}\] Given, \[{{T}_{1}}={{T}_{2}}\], \[{{p}_{1}}=1\,\,atm\], \[{{V}_{1}}=10\,\,cc\], \[{{p}_{2}}=4\,atm\] \[{{V}_{2}}=\frac{{{p}_{1}}{{V}_{1}}}{{{p}_{2}}}=\frac{1\times 10}{4}=2.5\,\,cc\]
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