A) \[2{{p}_{a}}{{V}_{a}}={{p}_{b}}{{V}_{b}}\]
B) \[{{p}_{a}}\ne {{p}_{b}},{{V}_{a}}={{V}_{b}}\]
C) \[\frac{{{p}_{a}}}{{{V}_{a}}}=\frac{{{p}_{b}}}{{{V}_{b}}}\]
D) \[{{p}_{a}}{{V}_{a}}={{p}_{b}}{{V}_{b}}\]
Correct Answer: D
Solution :
When gases are in thermal equilibrium, then they obey Boyles law according to which pV = constant \[\therefore \] \[{{p}_{1}}{{V}_{1}}={{p}_{2}}{{V}_{2}}\] Given, \[{{p}_{1}}={{p}_{a}},\,\,{{V}_{1}}={{V}_{a}},\,\,\,{{p}_{2}}={{p}_{b}},\,\,{{V}_{2}}={{V}_{b}}\] \[\Rightarrow \] \[{{p}_{a}}{{V}_{a}}={{p}_{b}}{{V}_{b}}\]
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