A) \[{{v}_{d}}={{E}^{2}}\]
B) \[{{v}_{d}}\propto E\]
C) \[{{v}_{d}}\propto \frac{1}{E}\]
D) \[{{v}_{d}}\propto {{E}^{2}}\]
Correct Answer: B
Solution :
When ends of a metallic wire are connected to a battery, the potential difference of the battery does not given an accelerated motion to the electrons, but simply gives them a small constant velocity towards higher potential known as drift velocity \[({{v}_{d}})\] \[\frac{I}{neA}=\frac{J}{ne}=\frac{\sigma E}{ne}\] ... (i) Also, V = E\[l\] ... (ii) \[\therefore \] \[{{v}_{d}}\propto E\]
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