A) zero
B) minimum
C) maximum
D) None of these
Correct Answer: C
Solution :
The acceleradon of a particle executing SHM is given by \[\alpha =-{{\omega }^{2}}y\] where cd is angular velocity, y the displacement. Maximum displacement = amplitude = a \[\therefore \] \[\alpha =-{{\omega }^{2}}a\]You need to login to perform this action.
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