A) \[\text{2}\times \text{l}{{\text{0}}^{-\text{8}}}\text{J}\]
B) \[2\times {{10}^{4}}J\]
C) 200 J
D) 2000 J
Correct Answer: B
Solution :
Work done W = pressure (p) \[\times \] volume-change (AV) Given, p = 2 atm \[=2\times {{10}^{5}}N/{{m}^{2}}\], \[\Delta V={{V}_{2}}-{{V}_{1}}\] = 150 - 50 = 100 L \[=100\times {{10}^{-3}}{{m}^{3}}\] \[\therefore \] \[W=p\,\Delta V\] \[W=2\times {{10}^{5}}\times 100\times {{10}^{-3}}\] \[=2\times {{10}^{4}}J\]
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