A) 100 eV
B) 14375 eV
C) 12000 eV
D) 12375 eV
Correct Answer: D
Solution :
The energy of bombarding electron is \[E=\frac{hc}{\lambda }\]where h is Plancks constant, c the speed of light, \[\lambda \] the wavelength. Given, \[h=6.6\times {{10}^{-34}}J-s\], \[c=3\times {{10}^{8}}m/s\], \[\lambda ={{10}^{-10}}m\], \[1\,\,eV=1.6\times {{10}^{-19}}J\] \[\therefore \] \[E=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{{{10}^{-10}}\times 1.6\times {{10}^{-19}}}\] \[\Rightarrow \] E = 12375 eV
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