A) \[\text{17}.\text{61}\times \text{l}{{\text{0}}^{\text{-3}}}\text{ kg}\]
B) \[10.61\times {{10}^{-3}}kg\]
C) \[\text{12}.\text{61}\times \text{1}{{0}^{-3}}\text{kg}\]
D) None of the above
Correct Answer: A
Solution :
From Faradays law of electromagnetic induction, mass of electrons released is \[m=Z\,I\,t\]where \[I\] is current, t is time and z electrochemical equivalent. Also, \[P=VI\] \[\therefore \] \[I=\frac{P}{V}=\frac{100\times {{10}^{3}}}{125}=800\,A\] \[m=Z\,I\,t\] \[=0.367\times {{10}^{-6}}\times 800\times 60\] \[=17.61\times {{10}^{-3}}kg\]
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