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AMU Medical AMU Solved Paper-2004

  • question_answer
    The capacity of a condenser is \[\text{4}\times \text{1}{{0}^{-6}}\] F and its potential is 100 V. The energy released on discharging it fully will be

    A)  0.04 J                                   

    B)  0.02 J

    C)  0.025 J                                 

    D)  0.05 J

    Correct Answer: B

    Solution :

                     Energy released on discharging the capacitor fully is given by                 \[E=\frac{1}{2}C{{V}^{2}}\] Given,   \[C=4\times {{10}^{-6}}F\],          V = 100 volt \[\therefore \]  \[E=\frac{1}{2}\times 4\times {{10}^{-6}}\times {{(100)}^{2}}\] \[\Rightarrow \]               \[E=2\times {{10}^{-2}}=0.02J\]


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