A) 0.04 J
B) 0.02 J
C) 0.025 J
D) 0.05 J
Correct Answer: B
Solution :
Energy released on discharging the capacitor fully is given by \[E=\frac{1}{2}C{{V}^{2}}\] Given, \[C=4\times {{10}^{-6}}F\], V = 100 volt \[\therefore \] \[E=\frac{1}{2}\times 4\times {{10}^{-6}}\times {{(100)}^{2}}\] \[\Rightarrow \] \[E=2\times {{10}^{-2}}=0.02J\]You need to login to perform this action.
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