A) \[\frac{8}{3}V\]
B) \[4\,V\]
C) \[6\,V\]
D) \[8\,V\]
Correct Answer: D
Solution :
In the given circuit, capacitors of \[3\,\mu F\] and \[6\,\mu F\] are connected in parallel, and this combination is connected in series with \[4.5\,\mu F\] capacitor. Hence effective capacitance is \[C=3+6=9\mu F\] \[\frac{1}{C}=\frac{1}{9}+\frac{1}{4.5}=\frac{9+4.5}{9\times 4.5}\] \[C=\frac{9\times 4.5}{9+4.5}=3\,\mu F\] The charge through the circuit is given by \[q=CV=3\times 12=36\,\mu C\] Potential difference across \[4.5\,\mu F\] capacitor \[V=\frac{q}{C}=\frac{36}{4.5}=8\,V\]You need to login to perform this action.
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