A) N-ethyl acetamide
B) acetamide
C) methyl acetamide
D) None of the above
Correct Answer: A
Solution :
Key Idea Primary and secondary amines (which contain replaceable hydrogen atoms) react with acid chloride or acid anhydride to form substituted amides. Ethyl amine on acetylation gives N-ethyl acetamide. \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}+\underset{acetyl\text{ }chloride}{\mathop{Cl-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}}}\,\] \[\underset{N-\text{ }ethylacetamide}{\mathop{\xrightarrow{{}}{{C}_{2}}{{H}_{5}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{N}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}+HCl}}\,\] or \[{{C}_{2}}{{H}_{5}}-N{{H}_{2}}+\underset{\begin{smallmatrix} acetic \\ anhydride \end{smallmatrix}}{\mathop{{{(C{{H}_{3}}CO)}_{2}}O}}\,\] \[\xrightarrow{{}}{{C}_{2}}{{H}_{5}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{N}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}+C{{H}_{3}}COOH\]
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