A) act as oxidant
B) act as reductant
C) gain electron
D) not act as reductant
Correct Answer: B
Solution :
In the presence of moisture, \[S{{O}_{2}}\] act as a reducing agent as it liberate nascent hydrogen. It reduces hydrogen peroxide into water. \[S{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}{{H}_{2}}S{{O}_{4}}+2H\] \[{{H}_{2}}{{O}_{2}}+2H\xrightarrow{{}}2{{H}_{2}}O\] Note - The bleaching action of \[S{{O}_{2}}\] is due to its reducing property. \[S{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}{{H}_{2}}S{{O}_{4}}+2[H]\] Colouring matter \[+2H\] colourless compound.
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