A) dehydration reaction
B) dehydrogenation reaction
C) hydrogenation reaction
D) homolytic fission reaction
Correct Answer: A
Solution :
Diethyl ether can be prepared by the dehydration of ethanol with cone. \[{{H}_{2}}S{{O}_{4}}\] at 410 K. In this method excess of alcohol is heated with cone. \[{{H}_{2}}S{{O}_{4}}\] at 410 K. \[{{C}_{2}}{{H}_{5}}\,O-{{C}_{2}}{{H}_{5}}\] \[\xrightarrow[410\,\,K]{{{H}_{2}}S{{O}_{4}}}{{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}\] Note - In this reaction the temperature must be controlled because at higher temperature (443 K), the alcohols get dehydrated to alkenes. \[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[443\,\,K]{{{H}_{2}}S{{O}_{4}}}C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}O\]
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