A) 9.6kg
B) 96.0kg
C) 6.4kg
D) 2.8kg
Correct Answer: A
Solution :
On the combustion of ethylene carbon dioxide and water are formed. \[{{C}_{2}}{{H}_{4}}\,\,\,\,\,+\,\,\,\,\,\,3{{O}_{2}}\xrightarrow{{}}2C{{O}_{2}}+2{{H}_{2}}O\] \[12\times 2+4=28\] 96 \[\because \]The weight of oxygen required for complete combustion of 28 g of ethylene = 96 g \[\therefore \] The weight of oxygen required for complete combustion of 2.8 kg of ethylene \[=\frac{96\times 2.8\times 1000}{28}\] = 9600 g = 9.6 kg
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