A) 9 J
B) \[9\times {{10}^{3}}J\]
C) \[9\times {{10}^{5}}J\]
D) \[9\times {{10}^{10}}J\]
Correct Answer: D
Solution :
From Einsteins mass-energy equivalence relation, the amount of matter converted into energy is given by \[\Delta \,E=\Delta \,m{{c}^{2}}\] Given, \[\Delta \,m=1mg={{10}^{-6}}kg\], \[c=3\times {{10}^{8}}m/s\] \[\therefore \] \[\Delta E=({{10}^{-6}})\,{{(3\times {{10}^{8}})}^{2}}\] \[\Rightarrow \] \[\Delta E=9\times {{10}^{10}}J\]
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