AMU Medical AMU Solved Paper-2004

  • question_answer
    The decomposition of \[{{N}_{2}}{{O}_{5}}\] occurs as, \[2{{N}_{2}}{{O}_{5}}\xrightarrow{{}}4N{{O}_{2}}+{{O}_{2}}\], and follows first order kinetics, hence

    A)  the reaction is unimolecular

    B)  the reaction is bimolecular

    C)  \[{{t}_{1/2}}\propto {{a}^{0}}\]

    D)  None of the above

    Correct Answer: C

    Solution :

                     Decomposition of N205 follows first order kinetics.                 \[2{{N}_{2}}{{O}_{5}}\xrightarrow{{}}4N{{O}_{2}}+{{O}_{2}}\] The half-life period of nth order of reaction is inversely proportional to (n - 1) th power of initial concentration. \[{{t}_{1/2}}\propto \frac{1}{{{a}^{n-1}}}\] where, n is order of reaction. Here,     \[n=1\]                 \[{{t}_{1/2}}\propto \frac{1}{{{d}^{1-1}}}\]                 \[{{t}_{1/2}}\propto {{a}^{0}}\] ie, half-life period of a first order reaction is independent of the initial concentration of the reactant. Note - For a first order reaction                 \[k=\frac{2.303}{t}\log \,\frac{{{[A]}_{0}}}{[A]}\]                 \[{{[A]}_{0}}=\] initial concentration of the  reactants                 [A] = concentration of reactants at  time t. 


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