A) \[1\times {{10}^{-8}}\]
B) \[1\times {{10}^{-4}}\]
C) \[1\times {{10}^{-6}}\]
D) \[1\times {{10}^{-5}}\]
Correct Answer: A
Solution :
Key Idea For a weak electrolyte according to Ostwalds dilution law. \[\alpha =\sqrt{K\,.\,\,V}\] or \[K={{\alpha }^{2}}C\] \[\left( V=\frac{1}{C} \right)\] where, K is known as dissociation constant C is concentration in mol/L \[\alpha \] degree of ionisation Here, a = 0.01% \[=0.0001=1\times {{10}^{-4}}\] C = 1.00M We know, \[{{K}_{a}}={{\alpha }^{2}}.\,\,C\] \[{{K}_{a}}={{(1\times {{10}^{-4}})}^{2}}\times 1\] \[{{K}_{a}}=1\times {{10}^{-8}}\]
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