A) 600 mA
B) 700 mA
C) 750 mA
D) 900 mA
Correct Answer: D
Solution :
Current (I) flowing in a tangent galvanometer is given by \[I=k\,\tan \theta \]. Given, k is reduction factor \[\therefore \] \[I=900\times {{10}^{-3}}\times \tan \,{{45}^{o}}\] \[\Rightarrow \] \[I=900\,\,mA\]You need to login to perform this action.
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