A) 17
B) 21
C) 25
D) 27
Correct Answer: D
Solution :
Key Idea Atomic weight = Equivalent weight \[\times \] valency. Here equivalent weight = 9 Specific heat of element \[=1.05\,\,J\,{{g}^{-1}}{{K}^{-1}}\] By using Valency of element \[=\frac{approximate\text{ }weight}{equivalent\text{ }weight}\] \[=\frac{\frac{26.8}{specific\text{ }heat}}{equivalent\text{ }weight}\] \[=\frac{26.8/1.05}{9}\] \[=2.835\approx 3\] \[\because \] Atomic weight = equivalent weight \[\times \]valency \[=9\times 3=27\]You need to login to perform this action.
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