A) 1L
B) 11.2 L
C) 22.4 L
D) unpredictable
Correct Answer: A
Solution :
Key Idea 1. Molecular weight = 2 \[\times \] vapour density Volume of 1 mole of gas at NTP = 22.4 L Vapour density of gas = 11.2 Hence, molecular weight \[=2\times 11.2\] = 22.4g \[\because \] The volume of 22.4 g gas at NTP = 22.4 L \[\therefore \] The volume of 1 g gas at NTP \[=\frac{22.4}{22.4}\times 1=1\,L\]You need to login to perform this action.
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