A) 0.1 M
B) 0.2 M
C) 1.0 M
D) 10.0 M
Correct Answer: C
Solution :
Key Idea \[pH=p{{K}_{a}}+\log \,\frac{[salt]}{[acid]}\] Here, pH = 5.5, \[p{{K}_{a}}=4.5\] Concentration of \[C{{H}_{3}}COOH=0.1\,\,M\] \[pH=p{{K}_{a}}+\log \,\frac{[C{{H}_{3}}COONa]}{[C{{H}_{3}}COOH]}\] \[5.5=4.5+\log \frac{[C{{H}_{3}}COONa]}{0.1}\] \[1.0=\log \frac{[C{{H}_{3}}COONa]}{0.1}\] \[10=\frac{[C{{H}_{3}}COONa]}{0.1}\] \[[C{{H}_{3}}COONa]=10\times 0.1=1.0\,M\]You need to login to perform this action.
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