A) \[19.6\times {{10}^{8}}N/{{m}^{2}}\]
B) \[19.6\times {{10}^{-10}}N/{{m}^{2}}\]
C) \[19.6\times {{10}^{10}}N/{{m}^{2}}\]
D) \[19.6\times {{10}^{-8}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
When strain is small, the ratio of normal stress to the volume-strain is called the bulk modulus of the material of the body. \[K=\frac{p}{\Delta V/V}\] where p is pressure \[\left( =\frac{F}{A} \right)\], and \[\frac{\Delta V}{V}\] the change in volume Given, \[\Delta V=0.1%\], \[V=0.001\] volt \[p=h\rho g\] \[p=200\times 1000\times 9.8\] \[=1.96\times {{10}^{6}}N/{{m}^{2}}\] \[\therefore \] \[K=\frac{1.96\times {{10}^{6}}}{0.001}\] \[=19.6\times {{10}^{8}}N/{{m}^{2}}\]
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